The full load current of a three-phase induction motor depends on several factors, including the motor’s power rating (in kilowatts or horsepower), voltage supply, and its efficiency.
Motor Full Load Current Calculator
| Input | Value |
|---|---|
| Customer Name | |
| Frame (Alpha Numeric) | |
| KW | |
| KV | |
| Efficiency | |
| PF |
Output
| Output | Value |
|---|---|
| Customer Name | |
| Frame (Alpha Numeric) | |
| KW | |
| KV | |
| Efficiency | |
| PF | |
| Full Load Current |
To calculate the full load current, you can use the following formula:
Full Load Current (FLC) = (P [kW]) / (√3 * KV * PF[0.85]*Efficiency[0.95])
Where:
- FLC is the full load current in amperes (A).
- P is the power rating of the motor in kilowatts (kW).
- V is the voltage supply in volts (KV).
- Efficiency is the motor’s efficiency as a decimal (e.g., 0.90 for 90%).
- Power factor as decimal
The actual full load current can vary based on motor characteristics and application specifics. For example, if you have a 10 kW, 400 V, 3-phase motor with an efficiency of 90%, Power Factor as 1 , the full load current would be:
FLC = (10 kW) / (√3 * 400 V * 0.90) ≈ 14.43 A
So, the full load current for this motor would be approximately 14.43 amperes.